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The resulting solution is clearly valid (that is, there won t be any overlapping intervals in it); we need only show that it s optimal (that is, we have as many intervals as possible) We ll try to apply the idea of staying ahead Let s say our intervals are, in the order in which they were added, i1 ik , and that the hypothetical, optimal solution gives the intervals j1 jm We want to show that k = m Assume that the optimal intervals are sorted by finishing (and starting) times15 To show that our algorithm stays ahead of the optimal one, we need to show that for any r k, the finish time of ir is at least as early as that if jr , and we can prove this by induction.



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Create the PessimisticLockerA.java class using the code shown below. Notice that it uses the final version of the JDBCManager class from earlier in this chapter. You will need to create that class also, if you have not already done so. This class creates the table for this example, in addition to querying and updating the table:





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<%@ taglib prefix="f" uri="http://java.sun.com/jsf/core" %> <%@ taglib prefix="h" uri="http://java.sun.com/jsf/html" %> <html> <head> <title>City Distance</title> </head> <body> <f:view> <h:form> <h:panelGrid columns="2"> <h:outputLabel for="srcCity">Source City</h:outputLabel> <h:inputText id="srcCity" value="#{distanceBean.srcCity}" /> <h:outputLabel for="destCity">Destination City</h:outputLabel> <h:inputText id="destCity" value="#{distanceBean.destCity}" /> <h:outputLabel>Distance</h:outputLabel> <h:outputText value="#{distanceBean.distance}" /> <h:commandButton value="Find" action="#{distanceBean.find}" /> </h:panelGrid> </h:form> </f:view> </body> </html> This JSP file contains an <h:form> component for users to input a source city and a destination city. These two fields are defined using two <h:inputText> components, whose values are bound to a JSF managed bean s properties. The distance result is defined using an <h:outputText> component because its value is read-only. Finally, you define an <h:commandButton> component whose action will be triggered on the server side when you click it. Resolving Spring Beans in JSF The JSF configuration file faces-config.xml, located in the root of WEB-INF, is where you configure your navigation rules and JSF managed beans. For this simple application with only one screen, there s no navigation rule to configure. You can simply configure the preceding DistanceBean here. <faces-config xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-facesconfig_1_2.xsd" version="1.2"> <application> <variable-resolver> org.springframework.web.jsf.DelegatingVariableResolver

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package Ch07; import java.sql.*; import java.io.*; public class PessimisticLockerA { static Connection conn; static Statement stmt; static Statement stmtA; static PreparedStatement pstmt; static ResultSet rsetA; static String sqlCreate = "create table RESERVE " + "(ROOMID varchar(5), RES_DATE date, RES_FLAG boolean, " + "RES_NAME varchar(30))"; static String sqlInsert = "insert into RESERVE values " + "( , , , )"; static String sqlUpdate = "update RESERVE set RES_FLAG= , " + "RES_NAME= WHERE ROOMID= AND RES_DATE= "; static String sqlSelect = "select ROOMID, RES_DATE, " + "RES_FLAG, RES_NAME from RESERVE WHERE RES_FLAG=false FOR UPDATE"; static String roomName; static java.sql.Date roomDate; public static void main(String[] args) { try { String url = "jdbc:pointbase:server://localhost/pointbaseDB"; String username = "PBPUBLIC"; String password = "PBPUBLIC"; conn = JDBCManager.getConnection(url, username, password, false); System.out.println("conn autocommit is " + conn.getAutoCommit()); setup(); userAQuery(); System.out.println("Sleeping for 15 seconds, " + "run PessimisticLockerB");

For r = 1, it is obviously correct: the greedy algorithm chooses i1, which is the element with the minimum finish time Now, let r > 1 and assume that our hypothesis holds for r - 1 The question then becomes, is it possible for the greedy algorithm to fall behind at this step That is, is it possible that the finish time for ir could now be greater than that of jr The answer is clearly no, because the greedy algorithm could just as well have chosen jr (which is compatible with jr-1, and therefore also with ir-1, which finishes at least as early) So, the greedy algorithm keeps up with the best, all the way to the end However, this keeping up dealt only with finishing times, not the number of intervals.

try {Thread.sleep(15000);} catch (Exception e) {} System.out.println("PessimisticLockerA is awake"); userAUpdate(); } catch (Exception e) { e.printStackTrace(); } finally { JDBCManager.close(conn); } } static void setup() throws SQLException { System.out.println("Creating RESERVE table"); try { stmt = conn.createStatement(); stmt.addBatch(sqlCreate); stmt.executeBatch(); System.out.println("Inserting row of data"); pstmt = conn.prepareStatement(sqlInsert); pstmt.setString(1, "PIKE"); pstmt.setDate(2, new java.sql.Date(System.currentTimeMillis())); pstmt.setBoolean(3,false); pstmt.setNull(4, java.sql.Types.VARCHAR); pstmt.executeUpdate(); conn.commit(); } finally { JDBCManager.close(pstmt); JDBCManager.close(stmt); } } static void userAQuery() throws SQLException { System.out.println("User A is querying for rooms"); stmtA = conn.createStatement(); rsetA = stmtA.executeQuery(sqlSelect); if (rsetA.next()) { System.out.println("Query returned one row"); roomName = rsetA.getString(1); roomDate = rsetA.getDate(2); } // Neither the statement nor resultset are closed here // We need them open for the userAUpdate() method } static void userAUpdate() throws SQLException { try { if (roomName != null && roomDate != null) { System.out.println("User A is attempting to reserve room"); pstmt = conn.prepareStatement(sqlUpdate); pstmt.setBoolean(1, true); pstmt.setString(2, "User A"); pstmt.setString(3,roomName); pstmt.setDate(4, roomDate); int result = pstmt.executeUpdate(); if (result == 0) { System.out.println("Reservation did NOT succeed!"); System.out.println("The user will have to try " +

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