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When the function template min() is instantiated, the value for size will be replaced by a constant value known at compile-time A function definition or declaration follows the template parameter list Except for the presence of the template parameters as type specifiers or as constant values, the definition of a function template looks the same as that of a nontemplate function definition Let's look at an example

template <class Type, int size> Type min( const Type (&r_array)[size] ) {



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file:///F|/WinDDK/resources/CPPPrimer/c++primerhtm (454 / 1065) [2001-3-29 11:32:08]

/* parameterized function for finding * minimum value contained in array */ Type min_val = r_array[0]; for ( int i = 1; i < size; ++i ) if ( r_array[i] < min_val ) min_val = r_array[i]; return min_val; }

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In our example, Type indicates the return type of min(), the type of its parameter r_array, and the type of the local variable min_val; size indicates the size of the array to which r_array refers In the course of the program, Type will be substituted with various built-in and user-defined types and size will be substituted with various constant values determined by the actual uses of min() (Recall that the two uses of a function are to invoke it and to take its address) This process of type and value substitution is referred to as template instantiation We look at template instantiation in the next section The function parameter list of our min() function template may look somewhat terse As we discussed in Section 73, an array parameter is always passed as a pointer to the first element of the array, and the first dimension of an array argument is not known within a function definition To alleviate this problem, we decided here to declare min()'s parameter as a reference to an array This solves the problem of users having to pass a second argument to specify the size of the array, but its drawback is that its use with arrays of ints of different sizes generates, or istantiates, different instances of min() The name of a template parameter can be used after it has been declared as a template parameter and until the end of the template declaration or definition A template type parameter serves as a type specifier for the remainder of the template definition; it can be used in exactly the same way as a built-in or user-defined type specifier, such as for variable declarations and casts A template nontype parameter serves as a constant value for the remainder of the template definition; it can be used when constant values are required, perhaps to specify the size of an array in an array declaration or as the initial value of an enum constant.

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// size specifies the size of the array parameter and // initializes a const int value template <class Type, int size> Type min( const Type (&r_array)[size] ) { const int loc_size = size; Type loc_array[loc_size]; // }

If an object, function, or type having the same name as the template parameter is declared in global scope, the global scope name is hidden In the following example, the type of tmp is not double, but it has the type of the template parameter Type:

14

typedef double Type; template <class Type> Type min( Type a, Type b ) { // tmp has the type of the template parameter Type // not that of the global typedef Type tmp = a < b a : b; return tmp; }

file:///F|/WinDDK/resources/CPPPrimer/c++primerhtm (455 / 1065) [2001-3-29 11:32:08]

An object or type declared within the function template definition cannot have the same name as that of a template parameter:

template <class Type> Type min( Type a, Type b ) { // error: redeclares template parameter Type typedef double Type; Type tmp = a < b a : b; return tmp; }

The name of a template type parameter can be used to specify the return type of the function template:

// ok: T1 represents the return type of min(), // T2 and T3 represent its parameter types template <class T1, class T2, class T3> T1 min( T2, T3 );

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